The breaks applied to a car produce an accleration of 6m/s squar in the opposite direction to the motion . If the car takes 3s to come to rest calculate : a. Initial velocity b. Didtance covered by the car before stoping

a = -6m/s^2

t = 3 sec

v = 0 m/s

Using first law of motion

v = u+at

0 = u -6*3

u = 18m/s

 

Hence initial velocity = 18m/s

 

Using third law of motion to compute the distance travelled 

v^2 - u^2 = 2as 

0-18^2 = 2*(-6) s

s = 324/12 = 27 m