The breaks applied to a car produce an accleration of 6m/s squar in the opposite direction to the motion . If the car takes 3s to come to rest calculate : a. Initial velocity b. Didtance covered by the car before stoping

Asked by  | 27th Jul, 2013, 02:17: PM

Expert Answer:

a = -6m/s^2
t = 3 sec
v = 0 m/s
Using first law of motion
v = u+at
0 = u -6*3
u = 18m/s
 
Hence initial velocity = 18m/s
 
Using third law of motion to compute the distance travelled 
v^2 - u^2 = 2as 
0-18^2 = 2*(-6) s
s = 324/12 = 27 m

Answered by  | 28th Jul, 2013, 05:56: PM

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