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CBSE Class 10 Answered

the angry arjun carried some arrows for fighting with Bheeshm. With half the arrow, he cut down the arrows thrown by Bheeshm on details following
Asked by | 30 Nov, 2012, 11:28: PM
answered-by-expert Expert Answer
let the total number of arrows be X.
Arrows used in cutting the arrows thrown by bhism+killing rath driver+knocking down rath +knocking down flug +knocking down bow of bhism=X/2+6+1+1+1=X/2+9
 
therfor, arrows left=X-(X/2+9)=(X-18)/2
 
now given that arrows left=1+4(X)^(1/2)
 
Equating both,   (X-18)/2=1+4(X)^(1/2)
 
or, (X-18)/2-1=4(X)^(1/2)
or,X-20=8(X)^(1/2)
Squaring both side
X^2-40X+400=64X
or, X^2-104X+400=0
or,X^2-100X-4X+400=0
or, X(X-100)-4(X-100)=0
or,(X-4)(X-100)=0
or X=4 or 100
 
total number of arrows can not be 4 because arjun used more than that
therefor total number of arrows=100
Answered by | 01 Dec, 2012, 12:02: AM

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