The angles of a quad in ap. With d=10°.

Can I not take a-3d, a-d, a+d, a+3d as the angles. I am getting the angles as 60,80,100,120!!! Value of a=90° after adding the 4 angles.

### Asked by drhimasingh | 26th Dec, 2019, 06:20: PM

### No.
Because if you will take the angles as a-3d, a-d, a+d, a+3d
In this case, the common difference is 2d i.e. 20^{o} But the common difference is given as 10^{o}
You can do this if you take 2d as 10^{o} and hence d will be 5^{o} for the angles a-3d, a-d, a+d, a+3d
Instead take the angles as a, a+d, a+2d, a+3d and so you will get a=75^{o}
Hence, the angles will be 75^{o}, 85^{o}, 95^{o}, 105^{o}.

^{o}But the common difference is given as 10

^{o}

^{o}and hence d will be 5

^{o}for the angles a-3d, a-d, a+d, a+3d

^{o}

^{o}, 85

^{o}, 95

^{o}, 105

^{o}.

### Answered by Renu Varma | 26th Dec, 2019, 06:37: PM

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