The amount of heat absorbed by 1g of water while vapourising?

Asked by Spankinaishu | 7th Jun, 2018, 08:28: PM

Expert Answer:

Heat absorbed while vapouraisation = m×Cp×ΔT + m×Lv .............(1)

where m is mass of water = 1 g = 10-3 kg
Cp is specific heat of water = 4200 J/(kg.K)
ΔT  is temperature difference = (100-20) °C = 353 K ( initial temperature is assumed as 20 °C)
Lv is latent heat of vapouraisation = 2260 kJ / kg
 
Substitute all the data in Eqn.(1) to get the answer 3743 J

Answered by Thiyagarajan K | 8th Jun, 2018, 10:48: AM

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