the active mass of 7.0 g of nitrogen in a 2.0L container would be

Asked by pkgupta_nproofings | 28th Oct, 2014, 10:11: PM

Expert Answer:

Moles of N2 = 7/28 = 0.25 mol
Active mass = conc. in mol L-1
                  = 0.25 mol / 2 L
                  = 0.125

Answered by Prachi Sawant | 29th Oct, 2014, 10:07: AM