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CBSE Class 9 Answered

The acceleration of a particle which moves along the positive x−axis varies its position as shown. If the velocity of the particle is 0.8 m/s at x=0, the velocity of the particle at x=1.4 m is (in m/s)
Asked by siddhi196 | 12 Jun, 2020, 11:19: PM
answered-by-expert Expert Answer
a t space x equals 0 comma space u equals 0.8 m divided by s a r e a space o f space a c c e l e r a t i o n minus space d i s p l a c e m e n t space g r a p h space g i v e s A r e a equals integral subscript u superscript v a d x A r e a equals integral subscript u superscript v v fraction numerator d v over denominator d x end fraction d x A r e a equals integral subscript u superscript v v squared over 2 0.4 x 0.4 plus 1 half open parentheses 0.4 plus 0.2 close parentheses cross times 0.4 plus 0.20.6 equals integral subscript u superscript v v squared over 2 0.4 x 0.4 plus 1 half open parentheses 0.4 plus 0.2 close parentheses cross times 0.4 plus 0.20.6 equals v squared over 2 minus u squared over 2 O n space s o l v i n g space y o u space c a n space f i n d space t h e space a n s w e r
Answered by Utkarsh Lokhande | 13 Jun, 2020, 03:59: PM

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