test

Asked by  | 10th Dec, 2009, 10:29: PM

Expert Answer:

sin2θ + cosec2θ is always either equal to 2 or greater than 2.

Since, sin2θ + cosec2θ = (sin4θ + 1) /sin2θ

Now, the lowest value of θ = 0o

In this case (sin4θ + 1) /sin2θ = ∞

For θ = 90o
(sin4θ + 1) /sin2θ = 2

So the values of sin2θ + cosec2θ vary from 2 to infinity.

Answered by  | 11th Dec, 2009, 10:09: AM

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