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NEET Class neet Answered

Teri point charges A and B, having charges +Q and -Q respectively, are placed at certain distance apart and force acting between them is F . If 25% charge of A is transferred to B then force between the charges becomes.
Asked by mdd4246308 | 24 Dec, 2021, 12:32: AM
Expert Answer
Force F betwen two point charges +Q and -Q that are separated by a distance d is given as
 
F = K × ( Q2 / d2 )
 
where K = 1/(4πεo ) is Coulomb's constant
 
( It is assumed magnitude of both charges are equal )
 
If 25% of +Q is transferred to -Q , then charges after trasferring are  +0.75Q  and  - 0.75Q
 
Hence changed force  Fnew   between charges is calculated as
 
Fnew = K × (3/4)2  ( Q2 / d2 ) = (9/16) F
 
Hence  new force becomes (9/16) times of original force
Answered by Thiyagarajan K | 24 Dec, 2021, 08:32: AM
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