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Ten years ago, mother was 12 times as old her daughter and ten years hence she will be twice as old as her daughter will be. Find the present ages.
Asked by Cl_narayan | 30 Jan, 2020, 10:33: AM
Let 10 years ago daughter's age was x years.
Ten years ago, mother was 12 times as old her daughter .
Hence, mother's age was 12x.
Present age of daughter and mother is (x + 10) years and (12x + 10) years respectively.
10 years later daughters and mother's age will be (x + 20) years and (12x + 20) years respectively.

Ten years hence mother will be twice as old as her daughter will be.
Hence,
12x + 20 = 2(x + 20)
12x + 20 = 2x + 40
10x = 20
x = 2
Present age of daughter and mother are 12 years and 34 years respectively.
Answered by Sneha shidid | 31 Jan, 2020, 12:02: PM

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