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Ten years ago, mother was 12 times as old her daughter and ten years hence, she will be twice as old as her daughter will be. Find the present ages.
Asked by Cl_narayan | 06 Feb, 2020, 06:34: PM Expert Answer

Let the present age of mother = x years and the present age of daughter = y years

According to the first condition, we get

x - 10 = 12(y - 10)
→ x - 12y = -120 + 10
→ x - 12y = -110                  ..... (i)

According to the second condition, we get
x + 10 = 2(y + 10)
→ x - 2y = 10 .... (ii)

Subtracting (ii) from (i), we get

-10y = -120
→ y = 12

x - 2(12) = 12
x = 12 + 24 = 34

Therefore, the present age of mother is 24 years and the present age of daughter is 12 years
Answered by Yasmeen Khan | 07 Feb, 2020, 10:40: AM
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