JEE Class main Answered
tanA+tanB+tanC
Asked by girishzene | 03 Sep, 2021, 05:14: AM
Expert Answer
A, B and C are angles of triangle
tan(A) + tan(B) + tan(C) = tan(A) + tan(B) + tan[ 180 - ( A + B ) ]
tan(A) + tan(B) + tan(C) = tan(A) + tan(B) - tan ( A + B )
LHS = - tan(A) tan(B) tan [ 180 - C ] = tan(A) tan(B) tan(C)
Hence we get , tan(A) + tan(B) + tan(C) = tan(A) tan(B) tan(C)
Answered by Thiyagarajan K | 16 Sep, 2021, 11:17: PM
JEE main - Maths
Asked by azizrajil03 | 28 Feb, 2019, 03:54: PM
ANSWERED BY EXPERT
