tanA+tanB+tanC

Asked by girishzene | 3rd Sep, 2021, 05:14: AM

Expert Answer:

A, B and C are angles of triangle
 
tan(A) + tan(B) + tan(C) = tan(A) + tan(B) + tan[ 180 - ( A + B ) ] 
 
tan(A) + tan(B) + tan(C) = tan(A) + tan(B)  - tan ( A + B ) 
 
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LHS = - tan(A) tan(B) tan [ 180 - C ] = tan(A) tan(B) tan(C)
 
Hence we get , tan(A) + tan(B) + tan(C) = tan(A) tan(B) tan(C)
 

Answered by Thiyagarajan K | 16th Sep, 2021, 11:17: PM

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