tantheta/sectheta+1  +  cottheta/cosectheta+1  = cosectheta+sectheta-secthetax tantheta.

Asked by shreya ghoshal | 20th Nov, 2014, 08:37: PM

Expert Answer:

C o n s i d e r space t h e space l e f t space h a n d space s i d e space o f space t h e space g i v e n space e q u a t i o n : fraction numerator tan theta over denominator s e c theta plus 1 end fraction plus fraction numerator c o t theta over denominator cos e c theta plus 1 end fraction equals fraction numerator tan theta over denominator s e c theta plus 1 end fraction cross times fraction numerator s e c theta minus 1 over denominator s e c theta minus 1 end fraction plus fraction numerator c o t theta over denominator cos e c theta plus 1 end fraction cross times fraction numerator c o s e c theta minus 1 over denominator c o s e c theta minus 1 end fraction equals fraction numerator tan theta open parentheses s e c theta minus 1 close parentheses over denominator s e c squared theta minus 1 end fraction plus fraction numerator c o t theta open parentheses c o s e c theta minus 1 close parentheses over denominator c o s e c squared theta minus 1 end fraction equals fraction numerator tan theta open parentheses s e c theta minus 1 close parentheses over denominator tan squared theta end fraction plus fraction numerator c o t theta open parentheses c o s e c theta minus 1 close parentheses over denominator c o t squared theta end fraction equals fraction numerator open parentheses s e c theta minus 1 close parentheses over denominator tan theta end fraction plus fraction numerator open parentheses c o s e c theta minus 1 close parentheses over denominator c o t theta end fraction equals fraction numerator s e c theta over denominator tan theta end fraction minus fraction numerator 1 over denominator tan theta end fraction plus fraction numerator c o s e c theta over denominator c o t theta end fraction minus fraction numerator 1 over denominator c o t theta end fraction equals c o s e c theta minus c o t theta 1 plus cos theta minus tan theta

Answered by Vimala Ramamurthy | 21st Nov, 2014, 09:08: AM

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