CBSE Class 12-science Answered
surface density
Asked by chandant | 01 Oct, 2010, 05:26: PM
Expert Answer
Dear Student,
Surface density of smaller spheres of water of radius R1 = S (Coulombs/cm2)
Charge on one sphere, Q = Surface density x Surface Area
= S x (4 π R12)
Surface Density of larger drop = Total charge / surface area
Total Charge after the two spheres combine = 2Q = 2 S (4 π R2) = 8 (S π R2)
Surface Area of bigger drop:
We need to find the radius of the bigger drop.
Now, Volume bigger drop = 2 x Volume smaller drop (since two drops combine)
(4πR23) / 3 = 2 x (4πR13) / 3
R2 = R1 (2)1/3
Surface area of bigger drop = (4 π R22) = (2)2/3 4 π R12
Surface Density of larger drop = Total charge / surface area
= 8 (S π R12) / (2)2/3 4 π R12
= 2 (2)-2/3 S = (2)1/3 S
= 21/3 x Surface Density of smaller drop
Surface Density of larger drop: Surface Density of smaller drop = 21/3
We hope that clarifies your query.
We hope that clarifies your query.
Regards,
Team,
Topperlearning
Answered by | 01 Oct, 2010, 07:52: PM
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