surface density

Asked by chandant | 1st Oct, 2010, 05:26: PM

Expert Answer:

Dear Student,
 
Surface density of smaller spheres of water of radius R1 = S (Coulombs/cm2)
Charge on one sphere, Q = Surface density x Surface Area
                                 = S x (4 π R12)
 
Surface Density of larger drop = Total charge / surface area

 
Total Charge after the two spheres combine = 2Q = 2 S (4 π R2) = 8 (S π R2)
Surface Area of bigger drop:
 
We need to find the radius of the bigger drop.
Now, Volume bigger drop = 2 x Volume smaller drop (since two drops combine)
        (4πR23) / 3            =        2 x  (4πR13) / 3 
        R2                        =        R1  (2)1/3
 
Surface area of bigger drop = (4 π R22) = (2)2/3 4 π R12

Surface Density of larger drop = Total charge / surface area
                                            = 8 (S π R12) / (2)2/3 4 π R12
                                            = 2 (2)-2/3 S = (2)1/3 S
                                            = 21/3 x Surface Density of smaller drop
Surface Density of larger drop: Surface Density of smaller drop = 21/3

We hope that clarifies your query.
Regards, 
Team,  
Topperlearning
 
 
 

Answered by  | 1st Oct, 2010, 07:52: PM

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