suppose f(x) is a polynomial of degree 5 and with leading coefficient 2009. suppose further that f(1)=1,f(2)=3, f(3)=5,f(4)=7, f(5)=9. what is the value of f(6)

Asked by manvendra singh | 19th Nov, 2013, 10:42: PM

Expert Answer:

Let f(x) = g(x) + 2x - 1. Since f(1)=1, f(2)=3, f(3)=5, f(4)=7, f(5)=9, it then follows that g(1) = g(2) = g(3) = g(4) = g(5) = 0.
Since f(x) is 5th degree with leading coefficient 2009, the same is true for g(x).
Therefore, g(x) = 2009(x - 1)(x - 2)(x - 3)(x - 4)(x - 5).

So now, we have
f(x) = 2009(x - 1)(x - 2)(x - 3)(x - 4)(x - 5) + 2x - 1
f(6) = 2009(5)(4)(3)(2)(1) + 12 - 1 = 241091

Answered by  | 19th Nov, 2013, 11:32: PM

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