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Sum of all real values of x satisfying the equation (x²–5x+5)^(x²+4x–60) = 1
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Asked by anandprashant2022 | 29 Jul, 2022, 21:44: PM
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open parentheses x squared plus 5 x plus 5 close parentheses to the power of open parentheses x squared minus 4 x plus 60 close parentheses end exponent equals 1 to the power of 0 rightwards double arrow x squared plus 5 x plus 5 equals 1 space space & space space x squared minus 4 x plus 60 equals 0 rightwards double arrow left parenthesis x plus 4 right parenthesis left parenthesis x plus 1 right parenthesis space & space left parenthesis x minus 10 right parenthesis left parenthesis x plus 6 right parenthesis equals 0 rightwards double arrow x equals negative 4 space o r space x equals negative 1 space & space x equals 10 space o r space x equals negative 6
Answered by Renu Varma | 05 Aug, 2022, 16:17: PM
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JEE main - Maths
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JEE main - Maths
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JEE main - Maths
Sum of all real values of x satisfying the equation (x²–5x+5)^(x²+4x–60) = 1
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Asked by anandprashant2022 | 29 Jul, 2022, 21:44: PM
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JEE main - Maths
(2x-3)^2 - |2x-3| -2 =0
Asked by mehraakshita419 | 23 Jul, 2022, 08:44: AM
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