CBSE Class 12-science Answered
sulphur dioxide is a reducing agent but tellurium dioxide is an oxidising agent,why?
Asked by ashwin srinath | 16 Aug, 2012, 08:46: PM
Expert Answer
Oxidation no. of sulphur changes from 0 to +4 in SO2. Due to presence of d-orbitals(vacant) sulphur can extend its covalency & show oxidation states till +6, which is stable in sulphur (eg: SF6).
Hence it acts as a reducing agent. (PS it acts as both oxidising and reducing agent)
Oxidation no. of Te changes from 0 to +4 in TeO2. Unlike sulphur Te cannot show +6 oxidation state as it is highly unstable due to inert pair effect. Therefore there can only be a decrease in it oxidation state (it can decrease to -2, +2). Also, TeO2 is a polymeric oxide which is not very much stable.
Hence it acts as an oxidising agent.
Hence it acts as a reducing agent. (PS it acts as both oxidising and reducing agent)
Oxidation no. of Te changes from 0 to +4 in TeO2. Unlike sulphur Te cannot show +6 oxidation state as it is highly unstable due to inert pair effect. Therefore there can only be a decrease in it oxidation state (it can decrease to -2, +2). Also, TeO2 is a polymeric oxide which is not very much stable.
Hence it acts as an oxidising agent.
Answered by | 17 Aug, 2012, 06:18: PM
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