CBSE Class 10 Answered
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Asked by suchet_r | 11 Aug, 2009, 07:59: PM
Expert Answer
Summation of all frequencies is 50. Hence,
5 + f1 + 10 + f2 + 7 + 8 = 50
f1 + f2 = 20 ........(1)
Mean of the frequency distribution = [summation of ( class mean x frequency) for each class]/frequency total
The class mean for 0-20 is 10, 20-40 is 30 and so on.
Hence,
(10x5 + 30xf1 + 50x10 + 70xf2 + 90x7 + 110x8)/50 = 62.8
30f1 + 70f2 = 1080 ........(2)
Solving (1) and (2)
we find, f1 = 8 ; f2 = 12
Regards,
Team,
TopperLearning.
Answered by | 11 Aug, 2009, 10:17: PM
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