State and prove the exterior angle property of a triangle.
Asked by Topperlearning User | 17th Nov, 2013, 11:17: PM
An exterior angle of a triangle is equal to the sum of its interior opposite angles.
Consider triangle ABC. ACD is an exterior angle.
Through C, draw CE||BA
To prove: 1 + 2 = ACD
Proof: 1 = x (pair of alternate interior angles since, CE||BA)
2 = y (pair of corresponding angles)
1 + 2 = x + y
i.e. 1 + 2 = ACD [ x + y = ACD]
Answered by | 18th Nov, 2013, 01:17: AM
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