SPEED AND VOLUME RELATED QUESTION
Asked by | 13th Apr, 2009, 04:23: PM
We assume that the depth is measured along the dimension which is 0.8 m side of the rectangular pipe.
Since the depth is 0.3 m, the water flow cross section is 0.3 x 1.2 = 0.36 m2,
while the pipe cross section is 0.8 x 1.2 = 0.96 m2.
Volume flow rate = Flow Cross section x velocity = 0.36 m2 x 3 m/min = 1.08 m3/min = 1.08 x 60 = 64.8 m3/hr
64.8 cubic meters of water flow in one hour.
Again the water flow cross section is 0.8 x 1.2 = 0.96 m2.
Volume flow rate = Flow Cross section x velocity = 0.96 m2 x 15 m/min = 14.4 m3/min = 14.4 x 60 = 864 m3/hr
Hence percentage increase = (864 - 64.8) x 100/64.8 = 1233 %
Answered by | 21st Aug, 2009, 12:26: PM
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