SPECIAL PRODUCT

Asked by  | 18th Jul, 2009, 07:29: AM

Expert Answer:

(x+1/x)2 =4

x2 +1/x2 =4 -2x.1/x

x2 +1/x2 = 2......A

(x+1/x)3 =8

x3 +1/x3  = 8 -3(x2.1/x +x.1/x2)...(a+b)3 =a3 +b3 +3a2b +3ab2

x3 +1/x3  = 8 -3(x.1/x)

x3 +1/x3  = 8 -3(2)

x3 +1/x3  = 2.......B

(x+1/x)4 = 16

x4 +1/x4  = 16 -(4x3.1/x +6.x2.1/x2 + 4.x.1/x3)

x4 +1/x4  = 16 -(4x2 +6 +4/x2)

x4 +1/x4  = 16 -6 -4((x2.1/x2)

x4 +1/x4  = 16 -6 -4(2)....from above

x4 +1/x4  = 2......C

Answered by  | 18th Jul, 2009, 08:01: PM

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