CBSE Class 9 Answered
Sorry sir, the previous question was wrong. the real question goes like this:
Asked by Sthitaprajna Mishra | 24 Sep, 2013, 08:20: AM
Expert Answer
1/(1 + x + y-1) + 1/(1 + y + z-1) + 1/(1 + z + x-1)
1/(1 + x + y-1) + 1/(1 + y + xy) + 1/(1 + 1/xy + 1/x)
(since xyz = 1)
= 1/(1 + x + 1/y) + 1/(1 + y + xy) + 1/(1 + 1/xy + 1/x)
= y/(y + xy + 1) + 1/(y + xy + 1) + xy/(xy + 1 + y)
= (y + 1 + xy)/(y + xy + 1)
= 1
1/(1 + x + y-1) + 1/(1 + y + xy) + 1/(1 + 1/xy + 1/x)
(since xyz = 1)
= 1/(1 + x + 1/y) + 1/(1 + y + xy) + 1/(1 + 1/xy + 1/x)
= y/(y + xy + 1) + 1/(y + xy + 1) + xy/(xy + 1 + y)
= (y + 1 + xy)/(y + xy + 1)
= 1
Hence, proved.
Answered by | 24 Sep, 2013, 09:00: AM
Application Videos
Concept Videos
CBSE 9 - Maths
Asked by gurucharansingh19975 | 23 Feb, 2024, 09:28: PM
ANSWERED BY EXPERT
CBSE 9 - Maths
Asked by satorugoku369 | 22 Feb, 2024, 08:56: PM
ANSWERED BY EXPERT
CBSE 9 - Maths
Asked by seebasajan1 | 11 Jan, 2024, 06:33: AM
ANSWERED BY EXPERT
CBSE 9 - Maths
Asked by lalitayadav7891 | 06 Dec, 2023, 07:30: PM
ANSWERED BY EXPERT
CBSE 9 - Maths
Asked by singha83147 | 04 Oct, 2023, 09:28: PM
ANSWERED BY EXPERT
CBSE 9 - Maths
Asked by mshibilshibil646 | 18 Jun, 2023, 09:37: AM
ANSWERED BY EXPERT
CBSE 9 - Maths
Asked by ashishk62054 | 06 Jun, 2023, 09:41: PM
ANSWERED BY EXPERT
CBSE 9 - Maths
Asked by priyadarshjagarwal | 04 Jun, 2023, 03:48: PM
ANSWERED BY EXPERT