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Asked by tangocharliee | 10th Nov, 2009, 02:37: PM

Expert Answer:

Let the r be the resistance of the thinner wire, then r = ρL/a = 10 Ω and that of thick wire is R = ρL/A.

The total resistance = r + R = ρL/a + ρL/A = (ρL/a)( 1 + (ρL/A)/(ρL/a)) = r(1 + a/A) = 10(1 + 1/3) = 40/3 Ω

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Answered by  | 10th Nov, 2009, 08:48: PM

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