CBSE Class 10 Answered
solve
Asked by palaksophia | 12 May, 2009, 11:34: AM
Expert Answer
(4-k)x2 + (2k+4)x + (8k+1)=0
a = (4-k) b= 2k+4 c = 8k+1
For the equation to be a perfect square
b2 = 4ac (2k+4)2 = 4(4-k)(8k+1)
k2+4+4k = 31k-8k2+4
9k2 = 27 k
k = 0 ; 3
Answered by | 15 May, 2009, 11:04: AM
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