CBSE Class 10 Answered
Solve
Asked by | 22 Jul, 2010, 03:52: PM
Expert Answer
Dear Student,
Here the given pair of equations are not linear. But we can change this to a linear pair using the substitution
Put
1 = p and
x + y
1 = q
x - y
the given equations become
10p + 2q = 4 .............(i)
15p - 5q = -2 .............(ii)
Let us solve these using elimination method
3(i) - 2(ii) gives
30p + 6q - 30p + 10q = 12 + 4
16q = 16
which means q = 1
Substituting this value of q in (i), we get
10p + 2(1) = 4
10p = 2
p = 1/5
So the solution to linear equations in p and q is
p = 1/5, q = 1
But we want the answer in x and y
So
1 = 1/5 which means x + y = 5 .......(iii)
x + y
and
1 = 1 which means x - y = 1 .........(iv)
x - y
We will solve (iii) and (iv) to get the final answer
Adding them, we get 2x = 6
So x = 3
Subtracting (iv) from (iii), we get 2y = 4
So y = 2
Hence, the final solution is x = 3, y = 2
Regards,
Team Topper Learning
Answered by | 22 Jul, 2010, 06:58: PM
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