Solve:

Asked by nkrbasak | 4th Mar, 2011, 06:26: PM

Expert Answer:

dear student,
Angle OAP =angle OBP=90 degrees..as the radius is perpendicular to the tangent at point of contact
angle APB=70 degrees given
so
angle AOB= 110 degrees...angle sum prop of quadrilateral
now
triangles POA,POB are congruent by SSS rule
since
PO=PO...common
PA=PB...tangent segments drawn from ext point
AO=BO..radii
so
angle POA=angle POB...CPCT
so
each of them is 55 degrees.

Answered by  | 4th Mar, 2011, 08:18: PM

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