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JEE Class main Answered

solve
Asked by adjacentcalliber10 | 25 May, 2019, 08:11: PM
Expert Answer
straight x to the power of 2 over 3 end exponent plus straight y to the power of 2 over 3 end exponent equals 1
diff space wrt space straight x
2 over 3 straight x to the power of fraction numerator negative 1 over denominator 3 end fraction end exponent plus 2 over 3 straight y to the power of fraction numerator negative 1 over denominator 3 end fraction end exponent dy over dx equals 0
straight x to the power of fraction numerator negative 1 over denominator 3 end fraction end exponent plus straight y to the power of fraction numerator negative 1 over denominator 3 end fraction end exponent dy over dx equals 0
dy over dx equals fraction numerator negative straight x to the power of fraction numerator negative 1 over denominator 3 end fraction end exponent over denominator straight y to the power of fraction numerator negative 1 over denominator 3 end fraction end exponent end fraction
dy over dx equals fraction numerator negative straight y to the power of 1 third end exponent over denominator straight x to the power of 1 third end exponent end fraction
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