CBSE Class 10 Answered
solve......
Asked by | 06 Sep, 2008, 12:28: PM
Expert Answer
in a right angle triangle we have
PR2= PQ2+QP2
let PR = x
x2= (25-x)2+52
on solving this we get x=13
so PR=13cm, QR=12cm and PQ=5cm
sinP=QR/PR = 12/13
cosP=PQ/PR = 5/13
tan P = QR/PQ = 12/5
Answered by | 06 Sep, 2008, 06:11: PM
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