Solve

Please cross check the polynomial should have the constant term as +7 instead of -7.

 

 

Divide the polynomial x^3-3x^2+3x+7 by (x+1).

You will get 0 as the remainder and x^2 - 4x + 7 as the quotient.

So, x^3-3x^2+3x-7=(x+1)(x^2 - 4x + 7)

Thus, on comparing the quotient with (ax^2+bx+c), we get, a = 1, b = -4 and c = 7

Thus, a + b + c = 4