Asked by nmenghani | 27th Apr, 2010, 11:33: AM
let the roots be m and 2m.
so sum of roots=-b/a=3m
m=-b / 3a..(i)
product of the roots =c /a=m x 2m..(ii)
substitute the value of m from (i) into (ii)
you will get the equation containing a,b,c.
this is the reqd condition.
Answered by | 27th Apr, 2010, 11:39: AM
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