solve
Asked by | 5th Jun, 2009, 11:13: PM
Expert Answer:
f(x)=6x^4-35x^3+62x^2-35x+6
Putting x=2, We have f(2)=0.
Putting x=3, we have f(3)=0
Hence (x-2)(x-3) is a factor of f(x).
Dividing f(x) by (x-2)(x-3),we gt quoitent as:
g(x)=6x2 -5x+1
=(-1 + 2 x) (-1 + 3 x)
Hence f(x)=(-3 + x) (-2 + x) (-1 + 2 x) (-1 + 3 x)
Answered by | 8th Jun, 2009, 02:03: AM
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