solve

Asked by  | 5th Jun, 2009, 11:13: PM

Expert Answer:

 f(x)=6x^4-35x^3+62x^2-35x+6

Putting x=2, We have f(2)=0.

Putting x=3, we have f(3)=0

Hence (x-2)(x-3) is a factor of f(x).

Dividing  f(x) by (x-2)(x-3),we gt quoitent as:

g(x)=6x2 -5x+1
=(-1 + 2 x) (-1 + 3 x)

Hence f(x)=(-3 + x) (-2 + x) (-1 + 2 x) (-1 + 3 x)

Answered by  | 8th Jun, 2009, 02:03: AM

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