solve: 3 over 4 open parentheses 7 x minus 1 close parentheses minus open parentheses 2 x minus fraction numerator 1 minus x over denominator 2 end fraction close parentheses equals x plus 3 over 2

Asked by badesraajay | 19th Jul, 2015, 05:23: PM

Expert Answer:

3 over 4 open parentheses 7 x minus 1 close parentheses minus open parentheses 2 x minus fraction numerator 1 minus x over denominator 2 end fraction close parentheses equals x plus 3 over 2 rightwards double arrow 21 over 4 x minus 3 over 4 minus 2 x plus 1 half minus x over 2 equals x plus 3 over 2 rightwards double arrow 21 over 4 x minus 2 x minus x over 2 minus x equals 3 over 2 minus 1 half plus 3 over 4 rightwards double arrow fraction numerator 21 x minus 8 x minus 2 x minus 4 x over denominator 4 end fraction equals fraction numerator 6 minus 2 plus 3 over denominator 4 end fraction rightwards double arrow 21 x minus 8 x minus 2 x minus 4 x equals 7 rightwards double arrow 7 x equals 7 rightwards double arrow x equals 1

Answered by satyajit samal | 20th Jul, 2015, 09:20: AM