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CBSE Class 10 Answered

solve y= 7y2 -6y -13sqrt 7
Asked by kckc_kk | 04 Jun, 2017, 10:12: AM
answered-by-expert Expert Answer
begin mathsize 14px style square root of 7 straight y squared minus 6 straight y minus 13 square root of 7 equals 0
equals square root of 7 straight y squared minus 13 straight y plus 7 straight y minus 13 square root of 7 equals 0
rightwards double arrow straight y open parentheses square root of 7 straight y minus 13 close parentheses plus square root of 7 open parentheses square root of 7 straight y minus 13 close parentheses equals 0
rightwards double arrow open parentheses square root of 7 straight y minus 13 close parentheses open parentheses straight y plus square root of 7 close parentheses equals 0
rightwards double arrow square root of 7 straight y minus 13 equals 0 space space or space space straight y plus square root of 7 equals 0
rightwards double arrow straight y equals fraction numerator 13 over denominator square root of 7 end fraction space space or space space straight y equals negative square root of 7 end style
Answered by Rashmi Khot | 04 Jun, 2017, 11:56: PM
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