solve x and y
 
x+y + y-1 = 8
  2        3
 
x-1 + y+1 = 9
  3       2

Asked by Benitta Biju | 20th Jun, 2014, 12:09: PM

Expert Answer:

T a k i n g space t h e space f i r s t space e q u a t i o n fraction numerator x plus y over denominator 2 end fraction space plus space fraction numerator y minus 1 over denominator 3 end fraction space equals space 8 space space rightwards double arrow fraction numerator 3 left parenthesis x plus y right parenthesis space plus space 2 left parenthesis y minus 1 right parenthesis over denominator 6 end fraction equals space 8 space space space space space left parenthesis L C M space o f space 2 comma space 3 right parenthesis rightwards double arrow space 3 x plus 3 y space plus space 2 y minus 2 space equals space 48 rightwards double arrow 3 x space plus space 5 y space equals space 50 space space space space space space.... space left parenthesis 1 right parenthesis  T a k i n g space t h e space s e c o n d space e q u a t i o n space fraction numerator x minus 1 over denominator 3 end fraction plus space fraction numerator y plus 1 over denominator 2 end fraction space equals space 9 rightwards double arrow fraction numerator 2 left parenthesis x minus 1 right parenthesis plus 3 left parenthesis y plus 1 right parenthesis over denominator 6 end fraction space equals space 9 rightwards double arrow 2 x space minus space 2 space plus space 3 y space plus space 3 space equals space 54 rightwards double arrow 2 x space plus space 3 y space equals space 53 space space space space space space space space space..... left parenthesis 2 right parenthesis  U sin g space c r o s s minus m u l t i p l i c a t i o n space m e t h o d comma fraction numerator x over denominator left parenthesis 5 right parenthesis left parenthesis 53 right parenthesis minus space left parenthesis 50 right parenthesis left parenthesis 3 right parenthesis end fraction space equals space fraction numerator y over denominator space left parenthesis 53 right parenthesis left parenthesis 3 right parenthesis minus left parenthesis 50 right parenthesis left parenthesis 2 right parenthesis end fraction equals fraction numerator minus 1 over denominator left parenthesis 3 right parenthesis left parenthesis 3 right parenthesis minus left parenthesis 2 right parenthesis left parenthesis 5 right parenthesis end fraction fraction numerator x over denominator 265 minus 150 end fraction space equals space fraction numerator y over denominator 100 minus 159 end fraction space equals space fraction numerator minus 1 over denominator 9 minus 10 end fraction x over 115 space equals space fraction numerator y over denominator minus 59 end fraction space equals fraction numerator minus 1 over denominator minus 1 end fraction i. e. space x over 115 equals 1 space space space ; space space fraction numerator y over denominator minus 59 end fraction space equals 1 x space equals space 115 space space space space ; space space space y space equals space minus 59 space

Answered by Mili Hariyani | 21st Jun, 2014, 09:24: AM