solve this

Asked by ambikagangadhar336 | 17th Mar, 2020, 09:45: PM

Expert Answer:

2 straight x squared minus 3 straight x minus 4 equals 0
straight alpha plus straight beta equals 3 over 2
αβ equals fraction numerator negative 4 over denominator 2 end fraction equals negative 2

New space QE
straight x squared minus open parentheses sum space of space roots close parentheses straight x plus open parentheses product space of space roots close parentheses equals 0
straight x squared minus open parentheses 1 over straight alpha squared plus 1 over straight beta squared close parentheses straight x plus open parentheses fraction numerator 1 over denominator straight alpha squared straight beta squared end fraction close parentheses equals 0
now
1 over straight alpha squared plus 1 over straight beta squared equals fraction numerator straight alpha squared plus straight beta squared over denominator straight alpha squared straight beta squared end fraction equals fraction numerator open parentheses straight alpha plus straight beta close parentheses squared minus 2 open parentheses αβ close parentheses over denominator open parentheses αβ close parentheses squared end fraction
fraction numerator 1 over denominator straight alpha squared straight beta squared end fraction equals 1 over open parentheses αβ close parentheses squared
Substitute space and space find space the space equation

Answered by Arun | 18th Mar, 2020, 08:42: AM