CBSE Class 10 Answered
solve this one
Asked by | 18 Nov, 2008, 08:41: PM
Expert Answer
p2x2+(p2-q2)x-q2=0
This equation is in a way already split into factors . The product : - p2q2 x2 is obtained by multiplying the two middle terms p2x and - q 2 x.
So just factorise as : p2x2 +p2x - q2x - q2=0
so , p2 x ( x +1) - q2 (x+1) =0
i.e (p2x-q2) (x+1)=0
ie. x = q2/ p2 or x = -1
Answered by | 19 Nov, 2008, 08:18: AM
CBSE 10 - Maths
Asked by hanugraha | 30 May, 2010, 07:53: PM
ANSWERED BY EXPERTCBSE 10 - Maths
Asked by hanugraha | 30 May, 2010, 07:13: PM
ANSWERED BY EXPERTCBSE 10 - Maths
Asked by shobhitdc | 29 May, 2010, 04:59: PM
ANSWERED BY EXPERTCBSE 10 - Maths
Asked by ROJAAPPA | 29 May, 2010, 12:58: PM
ANSWERED BY EXPERTCBSE 10 - Maths
Asked by shobhitdc | 29 May, 2010, 10:52: AM
ANSWERED BY EXPERTCBSE 10 - Maths
Asked by devanshmudgal | 28 May, 2010, 07:31: PM
ANSWERED BY EXPERTCBSE 10 - Maths
Asked by shobhitdc | 28 May, 2010, 01:12: PM
ANSWERED BY EXPERTCBSE 10 - Maths
Asked by shobhitdc | 28 May, 2010, 01:08: PM
ANSWERED BY EXPERT
