solve the following system of linear equations

Asked by geethika | 9th Feb, 2010, 05:16: AM

Expert Answer:

2ax - 2by = - (a+4b) 

2bx + 2ay =- (b-4a)

Solving by cross multiplication by a factor, 'b' for first equation and 'a' for second equation,

2abx - 2b2y = - b(a+4b)

2abx + 2a2y =- a(b-4a)

Subtracting these two,

2(a2+b2)y = 4(a2+b2)

y = 2

and to find x,

use,

2ax - 2by = - (a+4b)

2ax - 4b = - (a+4b)

2ax - 4b = - a - 4b

x = -1/2

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Answered by  | 9th Feb, 2010, 10:34: AM

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