Solve the following system of equation by the method of cross-multiplication:

Asked by nkrbasak | 22nd Sep, 2010, 03:27: PM

Expert Answer:

2(ax-by)+a+4b=0 ----------(1)2(bx+ay)+b-4a=0  ----------(2)Multiply equation (1) by a      and  equation (2) by bthen add the equations,x(2a2+2b2)+(a2+b2)=0hence x = -(a2+b2)2(a2+b2)=-12putting in equation (1)2by = 2ax+a+4b = 4bhence y = 2">

Answered by  | 22nd Sep, 2010, 09:29: PM

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