1. solve the equation of ncert exercise-5.3 question 9
 
 

Asked by Dharvi Kumra | 7th Jul, 2014, 12:10: PM

Expert Answer:

G i v e n space E q u a t i o n space i s space x squared plus x plus fraction numerator 1 over denominator square root of 2 end fraction equals 0 b squared minus 4 a c equals 1 minus 4 open parentheses fraction numerator 1 over denominator square root of 2 end fraction close parentheses equals 1 minus 2 square root of 2 r o o t s space a r e space g i v e n space b y space fraction numerator minus b plus-or-minus square root of b squared minus 4 a c end root over denominator 2 a end fraction equals fraction numerator minus 1 plus-or-minus square root of 1 minus 2 square root of 2 end root over denominator 2 end fraction equals fraction numerator minus 1 plus-or-minus i square root of 2 square root of 2 minus 1 end root over denominator 2 end fraction

Answered by Dharma Teja | 7th Jul, 2014, 02:35: PM