Solve problem of simple pendulum if damping force proportional to instantaneous tangential velocity is taken into account.If spring supports a mass of 5gm which perform damped oscillations.It is found to have successive maxima of 2.1cm & 1.3cm. If damping coefficient is 10(gm/s).find stiffness of the spring.

Asked by ankarika | 3rd Oct, 2010, 05:24: PM

Expert Answer:

Dear student,
 
Damping ratio = c / (2m * sqrt(k/m)) = c/(2m omega n)
Substituting the values,
k = 2.38 N/m
Hope this helps.
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Answered by  | 25th Nov, 2010, 03:28: PM

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