Asked by g_archanasharma | 22nd Mar, 2018, 10:11: PM
For balancing a redox reaction, you have to balance the no. of atoms on reactant and product side i.e, no. of atoms on both sides should be equal.
no.of Hydrogen atoms are not equal on both sides.
In CuO the oxidation no. of Cu is +2 while in Cu its 0 that means Cu gets reduced,
and in NH3 Oxidation no of N is -3 and in the product, it produced N2 with 0 oxidation no. hence it gets oxidised
There is no change in the O.S. of oxygen. lets balanced it by multiplying CuO by 3 we get,
Answered by Ramandeep | 23rd Mar, 2018, 09:26: AM
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