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CBSE Class 11-science Answered

Solve graphically the system of linear inequations:
Asked by Topperlearning User | 04 Jun, 2014, 01:23: PM
Expert Answer
The given system of inequations is:
Consider the equations x = 0; y = 0; y = 3; x + 2y = 2; 2x + 3y = 12.
Now, x + 2y =2 is a line through the points B (0, 1) and A (2, 0) which lie in the coordinate axes.
Now, O (0, 0) does not satisfy x + 2y > 2
    Graph of  is the half plane above line AB and including points of line AB.
X
0
2
Y
1
0
Also, 2x + 3y = 12 is a line through the points D (0, 4) and C (6, 0) which lie in the coordinate axes.
Now, O (0, 0) satisfies 2x + 3y < 12
    Graph of  is the half plane below line DC and including points of line DC.
X
0
6
Y
4
0
And, y = 3 is a line trough the point F (0, 3) and parallel to x-axis.
    Half plane to the right of y-axis including points of y-axis.
    Half plane above x-axis including points of x-axis.
    Graph lies in first Quadrant.
    The solution set is shaded in the figure.
 
Answered by | 04 Jun, 2014, 03:23: PM
CBSE 11-science - Maths
Asked by Topperlearning User | 04 Jun, 2014, 01:23: PM
ANSWERED BY EXPERT
CBSE 11-science - Maths
Asked by Topperlearning User | 04 Jun, 2014, 01:23: PM
ANSWERED BY EXPERT
CBSE 11-science - Maths
Asked by Topperlearning User | 04 Jun, 2014, 01:23: PM
ANSWERED BY EXPERT
CBSE 11-science - Maths
Asked by Topperlearning User | 04 Jun, 2014, 01:23: PM
ANSWERED BY EXPERT
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