Solve for x;- xsquare + 3!x! + 2 = 0

Asked by Prince Sonu | 24th Jul, 2013, 08:27: PM

Expert Answer:

|x|2 + 3|x| + 2 = 0
(|x| + 1) (|x| + 2) = 0
|x| = -1 or |x| = -2
Both are not possible. Hence, the given equation has no solution.

Answered by  | 25th Jul, 2013, 10:39: PM

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