CBSE Class 10 Answered
solve 6/x+y=7/x-y +3,1/2(x+y) =1/3(x-y),where x+y?0 and x-y?0.
Asked by | 19 Jun, 2011, 06:20: PM
Expert Answer
Let
So, now the given equations become:
6u 7v = 3 ... (1)
3u 2v = 0 ... (2)
Multiplying (2) by 2, we get,
6u = 4v
Putting this value in (1),
4v 7v = 3
3v = 3
v = 1
So, u = -2/3
Substituting the values of u and v in (A), we get,
x + y = -1 ... (3)
x - y = -3/2 or 2x - 2y = -3 ... (4)
Multiplying (3) by 2, we get,
2x + 2y = -2 ... (5)
Adding (4) and (5), we get,
4x = -5
Answered by | 19 Jun, 2011, 03:03: PM
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