solve 23 and 24

Asked by Anil | 21st Jun, 2017, 05:21: PM

Expert Answer:

begin mathsize 16px style
1 plus sin squared straight theta equals 3 sinθcosθ
Using space sin squared straight theta plus cos squared straight theta equals 1
rightwards double arrow sin squared straight theta plus cos squared straight theta plus sin squared straight theta equals 3 sinθcosθ
rightwards double arrow 2 sin squared straight theta plus cos squared straight theta equals 3 sinθcosθ
rightwards double arrow fraction numerator 2 sin squared straight theta over denominator cos squared straight theta end fraction plus fraction numerator cos squared straight theta over denominator cos squared straight theta end fraction equals fraction numerator 3 sinθcosθ over denominator cos squared straight theta end fraction
rightwards double arrow 2 tan squared straight theta plus 1 equals 3 tanθ
Solving space above space quadratic space equation space
tanθ equals straight x
you space will space get comma space tanθ equals 1 space or space tanθ equals 1 half

Note colon space Please space post space one space question space at space straight a space time. end style

Answered by Sneha shidid | 22nd Jun, 2017, 09:25: AM