CBSE Class 12-science Answered

The given circuit is redrawn and given above.

Potential difference across the points A and B is 10 V .

Similarly , potential difference across the points C and F is 10 V .

Capacitance between C and D is equivalent capaciatance of parallel combination of 15 μF and 5 μF.

Hence , Capacitance between C and D is 20 μF .

Capacitance between E and F is equivalent capaciatance of parallel combination of 10 μF and 10 μF.

Hence , Capacitance between E and F is 20 μF .

Since 20 μF capacitance is between C and D and also between E and F , potential difference 10 V between C and F is

divided symmetrically . Hence potential difference across C and D is 5 V .

Potential difference across the 5 μF capacitance is 5 V .

Charge on 5 μF capacitor = Capacitance × ( Potential difference ) = 5 μF ×5 V = 25 μC

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