CBSE Class 10 Answered
solution???
Asked by | 11 Apr, 2009, 11:07: AM
Expert Answer
Let the original price of a book = x Rs.
So, the increased price = x+10 Rs.
With the original price , the number of books that can be bought for Rs. 1200 is 1200/x
With the increased price the number of books that can be bought for Rs. 1200 is 1200/(x+10)
Acc to question,
1200/x-1200/(x+10)=10
1200*[(1/x)-(1/x+10)]=10
1200*[10]=10*x*(x+10)
1200=x(x+10)
Solving by quadratic factorisation we get,
x=30
So original price =Rs.30
Answered by | 11 Apr, 2009, 11:28: AM
CBSE 10 - Maths
Asked by hanugraha | 30 May, 2010, 07:53: PM
ANSWERED BY EXPERTCBSE 10 - Maths
Asked by hanugraha | 30 May, 2010, 07:13: PM
ANSWERED BY EXPERTCBSE 10 - Maths
Asked by shobhitdc | 29 May, 2010, 04:59: PM
ANSWERED BY EXPERTCBSE 10 - Maths
Asked by ROJAAPPA | 29 May, 2010, 12:58: PM
ANSWERED BY EXPERTCBSE 10 - Maths
Asked by shobhitdc | 29 May, 2010, 10:52: AM
ANSWERED BY EXPERTCBSE 10 - Maths
Asked by devanshmudgal | 28 May, 2010, 07:31: PM
ANSWERED BY EXPERTCBSE 10 - Maths
Asked by shobhitdc | 28 May, 2010, 01:12: PM
ANSWERED BY EXPERTCBSE 10 - Maths
Asked by shobhitdc | 28 May, 2010, 01:08: PM
ANSWERED BY EXPERT
