Solution please

Asked by brijk456 | 3rd Sep, 2019, 12:08: AM

Expert Answer:

Given:
 
Empirical formula = CH2O
 
Concentration of solution = 0.05 M
 
Both the solutions have same osmotic pressure.
 
Therefore,
 
straight W subscript straight x over straight M subscript straight x space equals space 0.05

3 over straight M subscript straight x space equals space 0.05

straight M subscript straight x space equals space fraction numerator 3 over denominator 0.05 end fraction

straight M subscript straight x space equals space 60
 
So the molecular weight of non-electrolytre is 60.
 
We know,
 
Molaecular formula = n × empirical formula 
 
Empirical formula weight (CH2O) = 30
 
straight n space equals space fraction numerator Molecular space mass over denominator Empirical space formula space mass end fraction

space space space equals 60 over 3

space space space space equals 2
 
Molecular formula = 2×(CH2O)
 
                           =C2H4O2
 
Moecular formula of compound is C2H4O2.

Answered by Varsha | 3rd Sep, 2019, 10:47: AM

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