Solution of the differential equation: dy/dx=(4x+y+1)^2
Asked by Saubhagya Borate
| 17th Apr, 2013,
01:04: PM
Expert Answer:
This differential equation can be solved by substitution
Let 4x+y+1=v
Then y=v-4x-1
Hence, dy/dx=dv/dx-4
Thus, the given DE becomes
dv/dx=v²+4
ie. dv/(v²+4) =dx
Integrating both sides
Let 4x+y+1=v
Then y=v-4x-1
Thus, the given DE becomes
Integrating both sides
Answered by
| 17th Apr, 2013,
09:02: PM
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