Solution of the differential equation: dy/dx=(4x+y+1)^2
Asked by Saubhagya Borate
| 17th Apr, 2013,
01:04: PM
Expert Answer:
This differential equation can be solved by substitution
Let 4x+y+1=v
Then y=v-4x-1
Hence, dy/dx=dv/dx-4
Thus, the given DE becomes
dv/dx=v²+4
ie. dv/(v²+4) =dx
Integrating both sides

Let 4x+y+1=v
Then y=v-4x-1
Thus, the given DE becomes
Integrating both sides

Answered by
| 17th Apr, 2013,
09:02: PM
Kindly Sign up for a personalised experience
- Ask Study Doubts
- Sample Papers
- Past Year Papers
- Textbook Solutions
Sign Up
Verify mobile number
Enter the OTP sent to your number
Change