CBSE Class 12-science Answered
Solenoid
Asked by | 22 Feb, 2010, 09:38: AM
Expert Answer
Dear Student
Magnetic field inside the solinoid B= mu 0 NI/L= 4π X10-7X(300X3)I/0.60.=I X 18.8X10-4 -------------4
To lift the wire F=BIL=mg= 2.5X10-3 X 10=2.5X10-2 N---(1)
BIL = B 6X0.02=0.12B-----------------2
1=2 ==> 0.12B=2.5X10-2 ==> B=0.208-----------3
3,4 ==> I X 18.8X10-4=0.208===> I=110.6A
So ans wer is b
Reagrds
Team Topperlearning.com
Answered by | 22 Feb, 2010, 06:29: PM
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