Asked by fathima12 | 19th Sep, 2010, 09:20: PM
let the smalles number required be x.
x-7 is divisible by 35,56 and 91.
also we require the smallest number.
x-7 is the LCM of 35,56,91
x-7=3640..as 3640 is the LCM of 35,56,91
thus the required number is 3647.
Answered by | 19th Sep, 2010, 09:29: PM
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