CBSE Class 10 Answered
smallest number
Asked by fathima12 | 19 Sep, 2010, 09:20: PM
Expert Answer
let the smalles number required be x.
ATQ,
x-7 is divisible by 35,56 and 91.
also we require the smallest number.
i.e.
x-7 is the LCM of 35,56,91
i.e.
x-7=3640..as 3640 is the LCM of 35,56,91
so
x=3647
thus the required number is 3647.
Answered by | 19 Sep, 2010, 09:29: PM
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