smallest number

Asked by fathima12 | 19th Sep, 2010, 09:20: PM

Expert Answer:

let the smalles number required be x.
x-7 is divisible by 35,56 and 91.
also we require the smallest number.
x-7 is the LCM of 35,56,91
i.e. 3640 is the LCM of 35,56,91
thus the required number is 3647.

Answered by  | 19th Sep, 2010, 09:29: PM

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